Dendritic Impedance in Neocortical L5 PT neurons (Kelley et al. accepted)

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Accession:266851
We simulated chirp current stimulation in the apical dendrites of 5 biophysically-detailed multi-compartment models of neocortical pyramidal tract neurons and found that a combination of HCN channels and TASK-like channels produced the best fit to experimental measurements of dendritic impedance. We then explored how HCN and TASK-like channels can shape the dendritic impedance as well as the voltage response to synaptic currents.
Reference:
1 . Kelley C, Dura-Bernal S, Neymotin SA, Antic SD, Carnevale NT, Migliore M, Lytton WW (2021) Effects of Ih and TASK-like shunting current on dendritic impedance in layer 5 pyramidal-tract neurons. J Neurophysiology (accepted)
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Model Information (Click on a link to find other models with that property)
Model Type: Neuron or other electrically excitable cell;
Brain Region(s)/Organism:
Cell Type(s): Neocortex L5/6 pyramidal GLU cell; Neocortex M1 L5B pyramidal pyramidal tract GLU cell;
Channel(s): I h; TASK channel;
Gap Junctions:
Receptor(s):
Gene(s):
Transmitter(s):
Simulation Environment: NEURON; Python; NetPyNE;
Model Concept(s): Impedance;
Implementer(s): Kelley, Craig;
Search NeuronDB for information about:  Neocortex L5/6 pyramidal GLU cell; Neocortex M1 L5B pyramidal pyramidal tract GLU cell; I h; TASK channel;
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L5PYR_Resonance-master
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AckerAntic
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:Comment :
:Reference : :		Kole,Hallermann,and Stuart, J. Neurosci. 2006

NEURON	{
	SUFFIX Ih
	NONSPECIFIC_CURRENT ihcn
	RANGE gIhbar, gIh, ihcn
}

UNITS	{
	(S) = (siemens)
	(mV) = (millivolt)
	(mA) = (milliamp)
}

PARAMETER	{
	gIhbar = 0.00001 (S/cm2)
	ehcn =  -37 :-45.0 (mV)
}

ASSIGNED	{
	v	(mV)
	ihcn	(mA/cm2)
	gIh	(S/cm2)
	mInf
	mTau
	mAlpha
	mBeta
}

STATE	{
	m
}

BREAKPOINT	{
	SOLVE states METHOD cnexp
	gIh = gIhbar*m
	ihcn = gIh*(v-ehcn)
}

DERIVATIVE states	{
	rates()
	m' = (mInf-m)/mTau
}

INITIAL{
	rates()
	m = mInf
}

PROCEDURE rates(){
	UNITSOFF
        if(v == -154.9){
            v = v + 0.0001
        }
		mAlpha =  0.001*6.43*(v+154.9)/(exp((v+154.9)/11.9)-1)
		mBeta  =  0.001*193*exp(v/33.1)
		mInf = mAlpha/(mAlpha + mBeta)
		mTau = 1/(mAlpha + mBeta)
	UNITSON
}