Layer 5 Pyramidal Neuron (Shai et al., 2015)

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Accession:180373
This work contains a NEURON model for a layer 5 pyramidal neuron (based on Hay et al., 2011) with distributed groups of synapses across the basal and tuft dendrites. The results of that simulation are used to fit a phenomenological model, which is also included in this file.
Reference:
1 . Shai AS, Anastassiou CA, Larkum ME, Koch C (2015) Physiology of layer 5 pyramidal neurons in mouse primary visual cortex: coincidence detection through bursting. PLoS Comput Biol 11:e1004090 [PubMed]
Model Information (Click on a link to find other models with that property)
Model Type: Neuron or other electrically excitable cell;
Brain Region(s)/Organism:
Cell Type(s): Neocortex V1 L6 pyramidal corticothalamic GLU cell;
Channel(s):
Gap Junctions:
Receptor(s):
Gene(s):
Transmitter(s): Glutamate;
Simulation Environment: NEURON; MATLAB;
Model Concept(s): Dendritic Action Potentials; Active Dendrites;
Implementer(s):
Search NeuronDB for information about:  Neocortex V1 L6 pyramidal corticothalamic GLU cell; Glutamate;
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ShaiEtAl2015
simulationcode
Ca_HVA.mod *
Ca_LVAst.mod *
CaDynamics_E2.mod *
epsp.mod *
glutamate.mod *
Ih.mod *
Im.mod *
K_Pst.mod *
K_Tst.mod *
Nap_Et2.mod *
NaTa_t.mod *
NaTs2_t.mod *
SK_E2.mod *
SKv3_1.mod *
AccessoryFunctions.hoc
DefineSections.hoc
distSynsCluster.hoc
distSynsCluster2.hoc
distSynsUniform.hoc
distSynsUniform2.hoc
distSynsUniformAlpha.hoc
Fig3A.hoc
neuron203.os
O_vd_C.dat
O_vs_C.dat
Run.hoc
varycolor.m
                            
:Comment :
:Reference : :		Kole,Hallermann,and Stuart, J. Neurosci. 2006

NEURON	{
	SUFFIX Ih
	NONSPECIFIC_CURRENT ihcn
	RANGE gIhbar, gIh, ihcn 
}

UNITS	{
	(S) = (siemens)
	(mV) = (millivolt)
	(mA) = (milliamp)
}

PARAMETER	{
	gIhbar = 0.00001 (S/cm2) 
	ehcn =  -45.0 (mV)
}

ASSIGNED	{
	v	(mV)
	ihcn	(mA/cm2)
	gIh	(S/cm2)
	mInf
	mTau
	mAlpha
	mBeta
}

STATE	{ 
	m
}

BREAKPOINT	{
	SOLVE states METHOD cnexp
	gIh = gIhbar*m
	ihcn = gIh*(v-ehcn)
}

DERIVATIVE states	{
	rates()
	m' = (mInf-m)/mTau
}

INITIAL{
	rates()
	m = mInf
}

PROCEDURE rates(){
	UNITSOFF
        if(v == -154.9){
            v = v + 0.0001
        }
		mAlpha =  0.001*6.43*(v+154.9)/(exp((v+154.9)/11.9)-1)
		mBeta  =  0.001*193*exp(v/33.1)
		mInf = mAlpha/(mAlpha + mBeta)
		mTau = 1/(mAlpha + mBeta)
	UNITSON
}

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