Principles governing the operation of synaptic inhibition in dendrites (Gidon & Segev 2012)

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Accession:226401
A simple result of Gidon & Segev 2012 was provided where distal (off-path) inhibition is demonstrated to be more effective than proximal (on-path) inhibition in a ball and stick neuron.
Reference:
1 . Gidon A, Segev I (2012) Principles governing the operation of synaptic inhibition in dendrites. Neuron 75:330-41 [PubMed]
Model Information (Click on a link to find other models with that property)
Model Type: Neuron or other electrically excitable cell;
Brain Region(s)/Organism:
Cell Type(s):
Channel(s):
Gap Junctions:
Receptor(s):
Gene(s):
Transmitter(s):
Simulation Environment: NEURON;
Model Concept(s): Simplified Models; Synaptic Integration;
Implementer(s): Morse, Tom [Tom.Morse at Yale.edu];
COMMENT
	All the channels are taken from same good old classic articles.
	The arrengment was done after:
	Kang, S., Kitano, K., and Fukai, T. (2004). 
		Self-organized two-state membrane potential 
		transitions in a network of realistically modeled 
		cortical neurons. Neural Netw 17, 307-312.
	
	Whenever available I used the same parameters they used,
	except in n gate:
		n' = phi*(ninf-n)/ntau
	Kang used phi = 12
	I used phi = 1
	
	Written by Albert Gidon & Leora Menhaim (2004).
ENDCOMMENT

UNITS {
 	(mA) = (milliamp)
 	(mV) = (millivolt)
	(S) = (siemens)		
}

NEURON {
	SUFFIX traub
	NONSPECIFIC_CURRENT i
	RANGE iL,iNa,iK
	RANGE eL, eNa, eK
	RANGE gLbar, gNabar, gKbar
	RANGE vshift
 }
	
	
PARAMETER {
        gNabar = .03 (S/cm2)	:Traub et. al. 1991
        gKbar = .015 (S/cm2) 	:Traub et. al. 1991
        gLbar = 0.00014 (S/cm2) :Siu Kang - by email.
        eL = -62.0 (mV) :Siu Kang - by email.
        eK = -80 (mV)	:Siu Kang - by email.
        eNa = 90 (mV)	:Leora
        totG = 0
        vshift = 0
}
 
STATE {
        m h n a b
}
 
ASSIGNED {
        v (mV)
        i (mA/cm2)
        cm (uF)
        iL iNa iK(mA/cm2)
        gNa gK (S/cm2)
	    minf hinf ninf 
		mtau (ms) htau (ms) ntau (ms) 
}


BREAKPOINT {
        SOLVE states METHOD cnexp 
        :-------------------------
        :Traub et. al. 1991
        gNa = gNabar*h*m*m
		iNa = gNa*(v - eNa)
		
        gK = gKbar*n : - Traub et. al. 1991
		iK = gK*(v - eK)
        :-------------------------
		iL = gLbar*(v - eL) 
		i = iL + iK + iNa
		:to calculate the input resistance get the sum of
		:	all the conductance.
		totG = gNa + gK + gLbar
			
}
 

INITIAL {
	rates(v+vshift)
	m = minf
	h = hinf
	n = ninf
}

? states
DERIVATIVE states {  
	rates(v+vshift)
	:Traub Spiking channels
	m' = (minf-m)/mtau
	h' = (hinf-h)/htau
	n' = 2*(ninf-n)/ntau :phi=12 from Kang et. al. 2004
}

? rates
DEFINE Q10 3
PROCEDURE rates(v(mV)) {  
	:Computes rate and other constants at current v.
	:Call once from HOC to initialize inf at resting v.
	LOCAL  alpha, beta, sum, vt, Q
	TABLE 	mtau,ntau,htau,minf,ninf,hinf
	FROM -100 TO 70 WITH 1000
	: see Resources/The unreliable Q10.htm for details
	: remember that not only Q10 is temprature dependent 
	: and just astimated here, but also the calculation of
	: Q is itself acurate only in about 10% in this range of
	: temperatures. the transformation formulation is:
	: Q = Q10^(( new(degC) - from_original_experiment(degC) )/ 10)
	
		:--------------------------------------------------------
		
		: This part was taken **directly** from:
		: Traub, R. D., Wong, R. K., Miles, R., and Michelson, H. (1991). 
		:	A model of a CA3 hippocampal pyramidal neuron incorporating 
		:	voltage-clamp data on intrinsic conductances. 
		:	J Neurophysiol 66, 635-650.
		:	Experiments were done in >=32degC for m,h
		: Traub et al uses their -60mV as 0mV thus here is the shift
		vt = v + 50
		Q = Q10^((35 - 32)/ 10)
		:"m" sodium activation system
		if(vt == 13.1){alpha = 0.32*4}
		else{alpha = 0.32*(13.1 - vt)/(exp((13.1 - vt)/4) - 1)}
		if(vt == 40.1){beta = 0.28*5}
		else{beta = 0.28*(vt - 40.1)/(exp((vt - 40.1)/5)-1)}
        sum = alpha + beta
		mtau = 1/sum
		mtau = mtau/Q
        minf = alpha/sum

       :"h" sodium inactivation system
		alpha = 0.128*exp((17 - vt)/18)
		beta = 4/(1 + exp((40 - vt)/5))
        sum = alpha + beta
		htau = 1/sum
		htau = htau/Q
        hinf = alpha/sum

    	:"n" potassium activation system
    	if(vt == 35.1){ alpha = 0.016*5 }
		else{alpha =0.016*(35.1 - vt)/(exp((35.1 - vt)/5) - 1)}
		beta = 0.25*exp((20 - vt)/40)
		sum = alpha + beta
        ntau = 1/sum
        ntau = ntau/Q
        ninf = alpha/sum
}



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