Breakdown of accmmodation in nerve: a possible role for INAp (Hennings et al 2005)

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Accession:55749
The present modeling study suggests that persistent, low-threshold, rapidly activating sodium currents have a key role in breakdown of accommodation, and that breakdown of accommodation can be used as a tool for studying persistent sodium current under normal and pathological conditions. See paper for more and details.
Reference:
1 . Hennings K, Arendt-Nielsen L, Andersen OK (2005) Breakdown of accommodation in nerve: a possible role for persistent sodium current. Theor Biol Med Model 2:16 [PubMed]
Model Information (Click on a link to find other models with that property)
Model Type: Neuron or other electrically excitable cell;
Brain Region(s)/Organism:
Cell Type(s): Spinal cord lumbar motor neuron alpha ACh cell; Myelinated neuron;
Channel(s): I Na,p; I Na,t; I K;
Gap Junctions:
Receptor(s):
Gene(s):
Transmitter(s):
Simulation Environment: MATLAB;
Model Concept(s): Action Potential Initiation; Action Potentials; Pathophysiology; Electrotonus;
Implementer(s): Hennings, Kristian [krist at hst.auc.dk];
Search NeuronDB for information about:  Spinal cord lumbar motor neuron alpha ACh cell; I Na,p; I Na,t; I K; 
function [T] = testm(M)
%TEST Test the model

fprintf('Strength-Duration Curce ...');
T.M = M;
tic
[T.SD.R,T.SD.T,T.SD.ts,T.SD.i] = SDstat(M,0);
fprintf('done (%.1fs).\n',toc);

fprintf('Threshold Electrotonus ...');
T.TE.TD = 1e-3*[0 10 20 30 40 60 99 101 110 120 150];
T.TE.P  = [0.4];
tic
[T.TE.E,T.TE.E0,T.TE.T,T.TE.V] = te2(M,T.TE.TD,T.TE.P,0);
fprintf('done (%.1fs).\n',toc);

fprintf('Strength-Intensity Curve ...');
T.SI.P = 0:0.2:0.8;
tic
[T.SI.T,T.SI.V,T.SI.E0] = si(M,T.SI.P);
fprintf('done (%.1fs).\n',toc);

fprintf('Accommodation curve ...');
T.AC.TS = 1e-3*[10 48.5 100 200 300];
tic
[T.AC.A,T.AC.S,T.AC.E] = acurve(M,T.AC.TS,T.SD.R,0);
fprintf('done (%.1fs).\n',toc);

fprintf('Recovery curve ...');
T.RE.Tisi = [3 4 5 6 7 8 9 10 20 30 40 50 60 70 100 200]*1e-3;
tic
[T.RE.E,T.RE.E0] = recovery(T.RE.Tisi,M,0);
fprintf('done (%.1fs).\n',toc);

fprintf('Accommodation slope ...');
T.SLOPE.TAU = 48.5e-3;
T.SLOPE.AC = T.AC.S(2);
T.SLOPE.E = T.AC.E(2);
%[T.SLOPE.AC,T.SLOPE.E] = slope(M,T.SLOPE.TAU,T.SD.R,0);
fprintf('done.\n');

plotTest3(T)

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